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1 vote
Find derivative from first principle:
x² tanx​

User Batressc
by
8.3k points

1 Answer

2 votes

Answer:

f'(x) = 2.x.tan(x) + x²/cos²(x)

Explanation:

f(x) = x².tan(x)

=> f'(x) = (x²)' . tan(x) + x². (tan(x))'

= 2x.tan(x) + x² . 1/cos²(x)

=> f'(x) = 2.x.tan(x) + x²/cos²(x)

User Shamara
by
8.2k points

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