Answer:
Pb(ClO₄)₂ (aq) + 2 NaCl (aq) -----> 2 NaClO₄ (aq) + PbCl₂ (s)
Step-by-step explanation:
This chemical reaction is a double-displacement reaction. In these reactions, the cation of one compound is swapped with the cation of another.
So, lead (II) (Pb²⁺) from lead (II) perchlorate (Pb(ClO₄)₂) will be swapped with sodium (Na⁺) from sodium chloride (NaCl). When creating the new compounds, there may need to be more than one ion of a particular type in order to make the overall compound neutral.
An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, you can add coefficients to modify the quantities of particular compounds.
The unbalanced reaction:
Pb(ClO₄)₂ (aq) + NaCl (aq) -----> NaClO₄ (aq) + PbCl₂ (s)
Reactants: 1 lead, 3 chlorine, 8 oxygen, 1 sodium
Products: 1 lead, 2 chlorine, 4 oxygen, 1 sodium
The balanced reaction:
Pb(ClO₄)₂ (aq) + 2 NaCl (aq) -----> 2 NaClO₄ (aq) + PbCl₂ (s)
Reactants: 1 lead, 4 chlorine, 8 oxygen, 2 sodium
Products: 1 lead, 4 chlorine, 8 oxygen, 2 sodium