Question

The planet XYZ travels about the star ABC in an orbit that

is almost circular. Assume that the orbit is a circle with
radius 94,000,000 mi. Assume there are 24 hours in one
day on planet XYZ.
(a) Assume that XYZ planet year is 346 days, and find the
angle formed by XYZ's movement in one day.
(b) Give the angular speed in radians per hour.
(c) Find the linear speed of XYZ in miles per hour.
please help me!!!

Answer 1

Answer:
v = 2.33 10⁷ mi / h

Explanation:

For this exercise we must observe that the velocity module is constant, so we can use the kinematic relation v = d / tThe distance traveled in each orbit is the length of the circle L = 2π rThe time it takes in orbit is called period (T)Let's reduce the quantities r = 8.9 10⁷ mi t = 24 h (3600s / 1 h) = 86400 sWe replace v = 2π r / TLet's calculate v = 2π 8.9 10⁷/86400 v = 6.47 10³ mi / s v = 6.47 10³ mi / s (3600 s / 1h) v = 2.33 10⁷ mi / h