Question

Please help

see attached picture​

Answer 1

See Explanation

Explanation:

• For cement block:

• Given is a square cement block, thus, it's width and height would be equal.

• -> length (l)= h, width (w)= 2x, height (h) = 2x

• 
  `V_(cement \: block) = lwh`

• 
  `\implies V_(cement \: block) = h(2x)(2x)`

• 
  `\implies V_(cement \: block) = 4x^2h.....(1)`

• For cylinder:

• Radius (r) = 2x/2 = x, height (h) = h

• 
  `V_(cylinder) = \pi r^2 h`

• 
  `\implies V_(cylinder) = \pi x^2 h.....(2)`

• Subtract (2) from (1), we find:

• 
  `V_(cement \: block)-V_(cylinder) = 4x^2h- \pi x^2 h`

• 
  `V(cement \: block\: without\: cylinder)= x^2h(4- \pi)`

• Thus proved

• To solve 6.2.1 and 6.2.2 plug the given values in
  `x^2h(4- \pi)` and calculate.