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A 10-N force is applied to two toy cars; Car A has a mass of 100 kg, and car B has a mass of 90 kg. Which car would have the greater acceleration and how much greater? Explain.

User Scott Walter
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Answer:


F = m_(A)a_(A) \rightarrow \: 10 = 100 a_(A) \\ \therefore \: a_(A) = 0.1m {s}^( - 2) \\F = m_(B)a_(B) \rightarrow \: 10 = 90 a_(B) \\\therefore \: a_(B) = 0.1111m {s}^( - 2)

User Chim
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