Question

8. Find the equation of the lines passing through the origin and (a) parallel (b) perpendicular to the lines represented by 6x² - 5xy + y2 + 5x - 2y + 1 = 0. .

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Answer 1

Hello,

Explanation:

1. We must decompose the conic into 2 lines.

`f(x,y)=x^2-5xy+y^2+5x-2y+1=0\\\\We\ are\ going\ to\ find\ the\ center\\\\\left\{\begin{array}{ccc}\frac{ \partial{f} }{\partial{x} }&=&12x-5y+5=0\\\\\frac{ \partial{f} }{\partial{y} }&=&-5x+2y-2=0\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x=0\\y=1\\\end {array} \right.\\\\We\ must\ find\ an\ other\ point\ of\ f(x,y).\\\\if\ y=0\ then\ x=(-1)/(2) \ or\ x=(-1)/(3)`

The 2 lines are: 2x-y+1=0 and 3x-y+1=0

Paralleles are y=2x and y=3x

Perpendiculars are x+2y=0 and x+3x=0