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∠BCD is an exterior angle of ∆ABC. If ∠BCD= 3∠A = x and ∠B = 80°, find the value of x.w

User Onexf
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Answer:


\tt{✧ \: S \: O \: L \: U \: T \: I \: O \: N : }


\large{ \tt{✿ \: 3x = x + 80 \degree}} [ Exterior angle is equal to the sum of two non - adjacent interior angles ]


\longrightarrow \: \tt{3x - x = 80 \degree}


\longrightarrow \tt{2x = 80 \degree}


\longrightarrow \tt{x = (80 \degree)/(2) }


\longrightarrow{ \boxed{ \tt{x = 40 \degree}}}

  • Hence , the value of x is 40° .

Hope this helps! ( ╹▽╹ )

∠BCD is an exterior angle of ∆ABC. If ∠BCD= 3∠A = x and ∠B = 80°, find the value of-example-1
User JT Nolan
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