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Say you are given the graph of the line y = -x. Write the equation of the line that is perpendicular to the given line and goes through the point (-8, 2).

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Key Concepts

  • Perpendicular lines
  • Linear equations
  • Slope-intercept form

Linear equations are often organized in slope-intercept form:
y=mx+b

  • m = slope
  • b = y-intercept

To find a linear equation, we often first solve for the slope, and then solve for the y-intercept algebraically.

To find the slope of a perpendicular line, we must find the negative reciprocal of the slope of the reference line.

Solving the Question

We're given:

  • Reference line is
    y=-x
  • Perpendicular line passes through
    (-8,2)

1) Find the slope of the reference line

We can rewrite the reference line to be clearer in slope-intercept form:


y=-1x+0

This means that -1 is the slope.

2) Find the slope of the perpendicular line

The negative reciprocal of -1 is 1. Therefore, the slope of the perpendicular line is 1. Plug this into slope-intercept form:


y=x+b

3) Solve for the y-intercept of the perpendicular line


y=x+b

Plug in the given point (-8,2) and solve for b:


2=-8+b\\b=2+8\\b=10

Therefore, the y-intercept of the perpendicular line is 10. Plug this back into our original equation:


y=x+10

Answer


y=x+10

User DoTryCatch
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