Question

What is the [H*] in a solution with pOH of 0.253?

A.
B.
OC
OD.
5.58 x 10-15 M
1.79 x 1014 M
3.21 x 102 M
5.58 x 10 M

Answer 1

poh = .253

p h2o= p[H+] +P[OH-]

ph2o is 14

14= pH+ + poH

14 = pH+ +.253

14-.253 =pH+

13.747 =ph+

and we know that

log [H+] = -pH+

[H+] = antilog pH+

H+ = antilog 13.747

H+ = 1.79×10-15