106k views
15 votes
The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Which equations can be used to solve for y, the length of the room? Select three options.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

User IAmoric
by
8.4k points

1 Answer

9 votes

length = y

width = y- 5

(y-5) * (y) = 750

y^2 - 5y = 750

y^2 -5y - 750 = 0

answer:

(y + 25)(y – 30) = 0

User Toby
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories