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If a 1.5 L saucepan is heated from 22 degrees celsius to 100 degrees celsius, by what percentage will any gas in the pan increase in volume?

User Vinceh
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1 Answer

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Step-by-step explanation:


(p1v1)/(n1t1) = (p2v2)/(n2t2) (ideal \: gas \: equation) \\ (v1)/(t1) = (v2)/(t2) \\ convert \: degrees \: to \: kelvin \: \\ (1.5l)/(297k) = (v2)/(373k) \\ v2 = 1.88l \\ it \: increased \: by \: 80\%

User Fulvio
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