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Write the reaction occurring at anode and cathode and the products of
electrolysis of aq KCl.

User VinsanityL
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1 Answer

4 votes

Answer:

4OH-→ 2H²O(l) + O² + 4e- (Anode)

2H+ → H²O (l) + 2e- (Cathode)

Step-by-step explanation:

OH- ions are preferentially discharged at the anode since they have a less positive electrode potential (+0.40V) then chloride ions (+1.36)

H+ ions are preferentially discharged at the cathode since they have a less negative standard electrode potential (0.00) than Potassium (-2.92)

User Frostmatthew
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