Question

I solved some of it but now I don't know if you continue it correctly ... To be performed: (lesson: Raducali of order "n")

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Answer 1

`( \sqrt[4]{7} + 2)( \sqrt[4]{7} - 2)( \sqrt[4]{7} + 4) \\ (first \: two \: is \: in \: the \: form \: of \: (x + y)(x - y) = {x}^(2) - {y}^(?) \\ then { \sqrt[4]{7} }^(2) - {2}^(2) \\ =( √(7) - 4) \\ so \: ( √(7) - 4)( √(7) + 4) \\ = { √(7) }^(2) - {4}^(2) \\ = 7 - 16 \\ = - 9 \\ thank \: you`