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find three consecutive integers such that the sum of the first and twice the second is 98 minus three times the third

User L Co
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let the numbers be : x, x + 1 and x + 2 ~

now, according to given condition :


\qquad \sf  \dashrightarrow \: x + 2(x + 1) = 98 - 3(x + 2)


\qquad \sf  \dashrightarrow \: x + 2x + 2 = 98 - 3x - 6


\qquad \sf  \dashrightarrow \: x + 2x + 3x = 98 - 6 - 2


\qquad \sf  \dashrightarrow \: 6x = 90


\qquad \sf  \dashrightarrow \: x = 90 / 6


\qquad \sf  \dashrightarrow \: x = 15

So, tge required numbers are : 15, 16 and 17

User Anique
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