Find three consecutive integers such that the sum of the first and twice the second is 98 minus three times the third

Question

asked Dec 3, 2023 233k views

1 Answer

Anique · Answer 1 · 2023-12-10T05:01:37+0000

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Let the numbers be : x, x + 1 and x + 2 ~

now, according to given condition :

$\qquad \sf  \dashrightarrow \: x + 2(x + 1) = 98 - 3(x + 2)$

$\qquad \sf  \dashrightarrow \: x + 2x + 2 = 98 - 3x - 6$

$\qquad \sf  \dashrightarrow \: x + 2x + 3x = 98 - 6 - 2$

$\qquad \sf  \dashrightarrow \: 6x = 90$

$\qquad \sf  \dashrightarrow \: x = 90 / 6$

$\qquad \sf  \dashrightarrow \: x = 15$

So, tge required numbers are : 15, 16 and 17