Question

Find the 11 term of the following geometric sequence.

10, 30, 90, 270, ...

PLEASE I NEED HELP

Answer 1

T1(a) = 10, common ratio (r) =
`(30)/(10) = 3` T11 = ?

Formula for finding the nth term of a GP:
`t_(n) = a {r}^(n - 1)`

To find T11:

`⟹t_(11) = 10 * {3}^(11 - 1)`

`⟹t_(11) = {10 * 3}^(10)`

`⟹t_(11) = 10 * 59049`

Therefore:

`t_(11) = 590490`