Question

in a circuit 3resistor are connected in parallel R¹=10ohms R²=15ohms R³=30ohms 1. calculate total resistance 2. total current flow 3.voltge drop across each resistor 4.total dissipated by the circuit 5. power in the 15ohms​

Answer 1

I'll give you the formula to calculate the net resistance of multiple resistors I'm in parallel.

1/R = 1/R1 + 1/R2 +1/R3 +……+1/Rn.

Take the reciprocal of each resistor value and add them up. The reciprocal value of a resistor is called its admittance. Add them up to get the total admittance. Notice that this value is 1/R. So take the reciprocal by dividing 1 by the total admittance value. Then you have the net resistance for all the parallel resistors.

Now you know the total resistance of the parallel values, if there are any other resistors in series with this, add them on to get the total resistance in the circuit.

Now use Ohm's law to find the current.

I =V/R

1. paralel resistance

1/(1/10+1/15+1/30)= 30/6=5 Ohms

2. total current : V/R=24/5= 4.8A