Question

A ball is rolled at a velocity of 2.0 m/s. After 3.6 seconds, it comes to a stop. What is the

acceleration of the ball?

Answer 1

Answer: Given -

• Initial velocity of the ball, u = 0 m/s
• final velocity of the ball, v = 12 m/s
• Time taken = 36 sec

To find -

• Acceleration of the ball.

Solution -

`A=(v-u)/(t)\\A=(12-0)/(36) \\A=(12)/(36) \\A=0.33m/s^2`

Therefore, the acceleration of the ball is 0.33 m/s².

I hope this helps.