Question

In the figure, m∠AOD=105. If m∠AOB=8x, m∠BOC=7x and m∠COD=6x, what is the value of x?

Answer 1

5

Explanation:

AOB+BOC+COD=AOD

6x+8x+7x=105

21x=105

x=105÷21

x=5

Answer 2

x = 5

Explanation:

from the diagram

∠ AOB + ∠ BOC + ∠ COD = ∠ AOD ( substitute values )

8x + 7x + 6x = 105

21x = 105 ( divide both sides by 21 )

x = 5