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What’s the distance between Y(3,0) and Z(-1,-2)

2 Answers

4 votes
square root of 20

hope this helps!
User Eric Swanson
by
4.8k points
1 vote

Answer:

Exact Distance =
2√(5) units

Approximate Distance = 4.4721 units

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Let's use the distance formula


(x_1,y_1) = (3,0) \text{ and } (x_2, y_2) = (-1,-2)\\\\d = √((x_1 - x_2)^2 + (y_1 - y_2)^2)\\\\d = √((3-(-1))^2 + (0-(-2))^2)\\\\d = √((3+1)^2 + (0+2)^2)\\\\d = √((4)^2 + (2)^2)\\\\d = √(16 + 4)\\\\d = √(20)\\\\d = √(4*5)\\\\d = √(4)*√(5)\\\\d = 2√(5)\\\\d \approx 4.4721\\\\

The exact distance is
2√(5) units.

That approximates to about 4.4721 units.

User Kamelkev
by
4.6k points