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A student measured the mass of a rock as 20 g. But the actual mass of the rock is 30 g. What was the student's percent deviation?

User Kbrose
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1 Answer

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Answer:

33.3%

Explanation:

%error =error/actual value*100

=30-20/30*100

=10/30*100

=33.3%

User Guilherme Lima
by
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