Question

What are the solutions to –24x – 24 = x3 + 8x2?

Answer 1

Answer: x=-2

Explanation:

`-24x-24=x^3+8x^2\\-24x-24+24=x^3+8x^2+24\\-24x=x^3+8x^2+24\\-24x+24x=x^3+8x^2+24+24x\\0=x^3+8x^2+24x+24\\x^3+8x^2+24x+24=0\\x^3+8x^2+12x+12x+24=0\\(x)(x^2+8x+12)+(12)(x+2)=0\\(x)(x^2+2x+6x+12)+(12)(x+2)=0\\(x)((x)(x+2)+6(x+2))+(12)(x+2)=0\\(x+2)((x)(x+6)+12)=0\\ (x+2)(x^2+6x+12)=0\\x+2=0\\x+2-2=0+(-2)\\x=-2\\x^2+6x+12=0\\D=(-6)^2-(4)(1)(12)\\D=36-48\\D=-12\\Hence,\\The\ equation\ has\ no\ valid \ roots\\Thus,\\x=-2`

Answer 2

–24x – 24 = x3 + 8x2

Explanation:

-24x-24=x^3+8x^2

x^3+8x^2+24=-24x-24+24

x^3+8x^2+24=-24x

x^3+8x^2+24+24x=-24x+24x

x^3+8x^2+24x+24=0