Question

K

ZRQT is a straight angle. What are mZRQS and
mZTQS?
mZRQS=
mZTQS=
ICCEID
R
30% /
(15x + 1)º
(10x + 4)º

Answer 1

• m∠RQS = 106°
• m∠TQS = 74°

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Use angle addition postulate:

• m∠RQT = m∠RQS + m∠TQS

Substitute the values and solve for x:

• 180 = 15x + 1 + 10x + 4
• 180 = 25x + 5
• 175 = 25x
• x = 175/25
• x = 7

Find the angle measures:

• m∠RQS = 15*7 + 1 = 106

• m∠TQS = 10*7 + 4 = 74