Question

Ivy has 4 blue marbles, 2 red marbles, and 3 green marbles. If Ivy randomly chooses 2 marbles without replacement, what is the probability that both are green?

Please help fast

Answer 1

3/9

Explanation:

Simply add up the marbles the total being 9 and the 3 green marbles.

Answer 2

1/12

Explanation:

Since these are dependent events, the fractions will vary on the second trial.

First trial 3 green marbles out of a total of 9 marbles. That's a 3/9 chances of the marble being green.

Second trial if you already pulled out a green. 2 green marbles are left with 6 other colors. That makes it a 2/8 odds.

Multiply the fractions and you get 6/72, which simplifies to 1/12.