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Two raise to x-3 multiply by 8 raised to x-2 =0.25​

User Blahblah
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1 Answer

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19 votes

Answer:


{2}^(x - 3) * {8}^(x - 2) = (1)/(4) \\ {2}^(x - 3) * {2}^(3x - 6) = (1)/(4) \\ {2}^(x - 3 + 3x - 6) = (1)/(4) \\{ 2}^(4x -9) = {2}^( - 2) \\ log_(2)({ 2}^(4x -9)) = log_(2)({ 2}^( - 2)) \\( 4x - 9 )log_(2)({ 2}) = ( - 2 )log_(2)({ 2})\\ 4x - 9 = - 2 \\ 4x = 7 \\ \therefore x = (7)/(4)

User Kristian Zondervan
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