Question

Given that
`c=(2d+1)/(3d-1)`,

1. calculate the value of c when d =
`(1)/(4)`
2. express d in terms of c

Answer 1

1.

`c = (2d + 1)/(3d - 1)`

`c = ((2 ((1)/(4))) + 1)/((3 ( (1)/(4))) - 1 )`

`c = ( (1)/(2) + 1)/( (3)/(4) - 1)`

`c = ( (1)/(2) + (2)/(2) )/( (3)/(4) - (4)/(4) )`

`c = ( (1 + 2)/(2) )/( (3 - 4)/(4) )`

`c = ( (3)/(2) )/( ( - 1)/(4) )`

`c = (3)/(2) * (4)/( - 1)`

`c = (3)/(1) * (2)/( - 1)`

`c = (6)/( - 1)`

`c = - 6`

Answer 2

C = -6

Explanation:

C = [2×1/4 + 1] ÷ [3×1/4 -1 ]

C = 3/2 ÷ -1/4

C = 3/2 × -4 = -6

C = 2d + 1 / 3d - 1

So, d = ( C + 1 ) / ( 3C - 2 )