Question

Need the answer quickly
Find the equilibrium price for s(q)=0.5q^2

Answer 1

Answer:x=q(2s-q)/2

Explanation:

x+o.5q^2=sq

x * 10+0.5q^2 * 10=sq * 10

10x+5q^2=sq * 10

10x+5q^2-5q^2=sq * 10-5q^2

10x=sq *10-5q^2

10x/10=sq * 10/10-5q^2/10

x=10sq-5q^2/10

x=5q(2s-q)/2

x=q(2s-q)/2

This * represents multiplication and x represents s(q).

Sorry, we havent done finding the equilibrium price in class, so i just show'd you finding the value.