Given :-
- The general term of a sequence is given by aₙ=43-3(n-1) .
To Find :-
- The first four terms of the sequence.
Solution :-
The given expression is
→ aₙ=43-3(n-1)
where n > 0
Finding the first term :
Substituting n = 1 , we have ,
→ T1 = 43 - 3(1-1)
→ T1 = 43 - 3*0
→ T1 = 43 - 0 = 43
Finding the second term :
Substituting n = 2 , we have,
→ T2 = 43 -3(2-1)
→ T2 = 43 -3*1
→ T2 = 43 -3 = 40
Finding the third term :
Substituting n = 3 , we have,
→ T3 = 43 -3(3-1)
→ T3 = 43 -3*2
→ T3 = 43 -6 = 37
Finding the fourth term :
→ T4 = 43 -3(4-1)
→ T4 = 43 -3*3
→ T4 = 43-9 = 34
Hence the first four terms of the sequence are 43 , 40 , 37 and 34 .
I hope this helps . Let me know if you need further clarification .