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Circle the GCF of 28x³ and 16x²y².​
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Circle the GCF of 28x³ and 16x²y².​

Circle the GCF of 28x³ and 16x²y².​-example-1
User Eel GhEEz
by
7.6k points

1 Answer

4 votes

Answer:


4x^(2)

Explanation:

You have to line up all your factors.


28x^3 =2*2*7*x*x*x\\16x^2y^2=2*2*2*2*x*x*y*y\\

Isolate what factors they have in common... and solve!


2*2*x*x\\4*x*x\\4x^2

Hope this helps!

User Umopepisdn
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