Question

What is an equation of the line that passes through the points (0, -3) and (-5, 3)

Answer 1

`y = - (6)/(5) x - 3`

Explanation:

Slope-intercept form

y= mx +c, where m is the gradient and c is the y-intercept.

`\boxed{gradient = (y1 - y2)/(x1 - x2) }`

`m = (3 - ( - 3))/( - 5 - 0)`

`m = (3 + 3)/( - 5)`

`m = - (6)/(5)`

Substitute the value of m into the equation:

`y = - (6)/(5) x + c`

To find the value of c, substitute a pair of coordinates.

When x= 0, y= -3,

`- 3 = - (6)/(5) (0) + c`

c= -3

Thus, the equation of the line is
`y = - (6)/(5) x - 3`.