Answer:
![\mathrm{V=\sqrt[3]{36}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/nt3qs9lbp9h7jx5wf16r9sa0dtq7cdztkv.png)
Explanation:
Determine if 36 is a cube root
(a-b)•(a^2+ab+b^2) =
a^3+a^2b+ab^2-ba^2-b^2a-b^3 =
a^3+(a^2b-ba^2)+(ab^2-b^2a)-b^3 =
a^3+0+0-b^3 =
a^3-b^3
→ Using this checker, we can see that 36 is not a cube root because it cannot be factored as the difference between two perfect cubes.
Solve
v^3 - 36 = 0
v^3 = 36
v = ∛36