Answer:
Explanation:
Attempt factorization by grouping
(((6•(a^4))•b)-((10•(a^3))•(b^2)))-((2•3a^2)•b^3)
(((6•(a^4))•b)-((2•5a^3)•b^2))-(2•3a^2b^3)
(((2•3a^4) • b) - (2•5a^3b^2)) - (2•3a^2b^3)
6a^4b - 10a^3b^2 - 6a^2b^3 = 2a^2b • (3a^2 - 5ab - 3b^2)
Pull out the leading term and put it with the original equation
= 2a^2b • (3a^2 - 5ab - 3b^2)
This would be one of the quicker ways to factor this equation.
Hope this helps.