Question

A box with mass m = 10

kg is pushed up a
slope to a height of h =
10 m. The slope makes
a 8 = 30° angle with
the horizontal and the
friction force along the
slope is f = 5 N. What
is the input work done
on the box?

Answer 1

20m

Step-by-step explanation:

u=20ms−1

v=0

f=μmgcosθ

mgsinθ+f=ma

mgsinθ+μmgcosθ=ma

530​+0.5×10×54​=a

6+4=a

a=10ms−2

v2−u2=2as

0−202=2×(−10)×s

s=20m