Question

A car accelerates from rest at -3m/s^2

1. What is the velocity at the end of 5 seconds?
2. What is the displacement after 5 seconds?

Answer 1

Answer: 1. -15m/s

2. -37.5m

Step-by-step explanation:

1. -3m*5=-15m/s

2. v=velocity. d=displacement. t=time. a=acceleration

d=vt+(1/2)at^2

d=0*5+(1/2)(-3)(5)^2 ==> car was at rest before accelerating

d=0+(1/2)(-3)(25)

d=(1/2)(-75)

d=-37.5 meters