Question

A sample of size n = 10 is drawn from a population. The data is shown below. 119.1 95.2 119.1 86.5 78.4 107.1 86.8 119.1 96.2 90.1 What is the range of this data set? range = What is the standard deviation of this data set? (Remember, it is a sample.) Please report the answer with appropriate rounding, reporting 2 more decimal places than the original data. Please, please, please do not calculate the value by hand. stdev = Question Help: Message instructor Submit Question​

Answer 1

Part 1

`range = 119.1 - 78 .4 = 40.7`

Part 2

First determine the mean average:

`mean = (119.1 + 95.2 + ... + 90.1)/(10) = 99.76`

`stdev = \sqrt{ \frac{ \sum(x - mean) {}^(2) }{n - 1} } = \sqrt{ \frac{(119.1 - 99.76) {}^(2) + ... }{10 - 1} } = 15.285`