Explanation:
Let x be the amount invested at 6% so that 18000-x is the amount invested at 7.5% both in dollars.
The total interest in 3 years is $3330 so we can write: 0.06x(3)+0.075(18000-x)(3)=3330
Solve for x:
0.06x(3)+0.075(18000−x)(3)=3330
Step 1: Simplify both sides of the equation.
0.06x(3)+0.075(18000−x)(3)=3330
0.06x(3)+−0.225x+4050=3330(Distribute)
0.18x+−0.225x+4050=3330
(0.18x+−0.225x)+(4050)=3330(Combine Like Terms)
−0.045x+4050=3330
−0.045x+4050=3330
Step 2: Subtract 4050 from both sides.
−0.045x+4050−4050=3330−4050
−0.045x=−720
Step 3: Divide both sides by -0.045.
−0.045x/−0.045=−720/−0.045
x=16000
x=16000
So, the amounts borrowed are:
Bank at 6% = 16000
Bank at 7.5% = 2000