Answer:
y = 3 and x = 4
Explanation:
Let's solve your system by substitution.
6x+5y=39;3x+5y=27
Step: Solve6x+5y=39for x:
6x+5y=39
6x+5y+−5y=39+−5y(Add -5y to both sides)
6x=−5y+39
6x/6=−5y+39/6
(Divide both sides by 6)
x=−5/6y+13/2
Step: Substitute −5/6y+13/2 for x in 3x+5y=27:
3x+5y=27
3(−5/6y+13/2)+5y=27
5/2y+39/2=27(Simplify both sides of the equation)
5/2y+39/2+−39/2=27+−39/2
(Add (-39)/2 to both sides)
5/2y=15/2
5/2y/5/2=15/2/5/2
(Divide both sides by 5/2)
y=3
Step: Substitute 3 for y in x=−5/6y+13/2:
x=−5/6y+13/2
x=−5/6(3)+13/2
x=4(Simplify both sides of the equation)