Question

the sum of three is 131 the second of three numbers is seven more than twice the first the third number is 12 less then the first what equation can be used to solos this problem

Answer 1

4x - 5 = 131 where x is the first number.

Explanation:

Let the first number be x.

Seconder number = 2x + 7.

Third number = x - 12.

So, the equation is :-

x + 2x + 7 + x - 12 = 131

4x - 5 = 131

4x = 136

x = 34

First number = 34, second = 2(34) + 7 = 75 and third number = 34-12 = 22.