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5 votes
PleSeee help ASAP now Tysm

PleSeee help ASAP now Tysm-example-1
User Gooly
by
6.6k points

2 Answers

3 votes

Answer:

9.055385 rounded to 6 decimal places

Explanation:

The distance between 2 points in a 2_D Cartesian coordinate can be determined by the distance formula


d = \sqrt {(x_(2) - x_(1))^2 + (y_(2) - y_(1))^2}

where
(x_1, y_1) \mathrm{\;and\:} (x_2, y_2) are the coordinates of the two points

This is also called Euclidean distance between the two points

Here coordinates of B are (-4, 6) and those of D are (-3, -3)

So distance between them


d = \sqrt {(-3 - (-4))^2 + (-3 - 6)^2}


= \sqrt {(1)^2 + (-9)^2}


= \sqrt {{1} + {81}}


= \sqrt {82}


= 9.055385 rounded to 6 decimal places

User Richard Muvirimi
by
6.5k points
5 votes

Answer:

BD =
√(82)

Explanation:

calculate BD using the distance formula

BD =
\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }

with (x₁, y₁ ) = B (- 4, 6 ) and (x₂, y₂ ) = D (- 3, - 3 )

BD =
√((-3-(-4))^2+(-3-6)^2)

=
√((-3+4)^2+(-9)^2)

=
√(1^2+81)

=
√(1+81)

=
√(82)

≈ 9.1 ( to 1 dec. place )

User KawishBit
by
6.9k points
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