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Find an equation of the line passing through the point (6,-1) that is parallel to the line y = -3/2x- 3​

User Nghiaht
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1 Answer

6 votes

Explanation:

parallel means it has the same slope.

the slope is always the factor of x : -3/2

I guess the needed equation is in slope-intercept form :

y = ax + b

"a" being the slope, "b" being the y intercept (the y value when x = 0).

but since we have a point on the line and its slope, we can start with the point-slope form

y - y1 = a(x - x1)

"a"is again the slope, (x1, y1) is the given point.

and then we transform this into the slope-intercept form.

in our case we have

y - -1 = -3/2 × (x - 6)

y + 1 = -3x/2 + 18/2 = -3x/2 + 9

y = -3x/2 + 8

or

y = -3/2 x + 8

or

y = -1/2 × (3x - 16)

User Joshua Swink
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