Question

Solve for all values of x by factoring

X^2 + 6x + 3 = 2x



SHOW WORK PLEASE

Answer 1

x^2+6x+3=2x
Step 1: move terms to the left

x^2+6x+3-2x=0
Step 2: combine like terms
6x-2x=4x
x^2+4x+3-2x=0
Step 3: use the quadratic formula
x=(-b±√(b^2-4ac))/2a
a=1, b=4, c=3
x=(-4±√(4^2-4(1)(3)))/2(1)
Step 4: simplify
x=-4±2/2
Step 5: separate the equations
x=-4+2/2
x=-4-2/2
Step 6: solve
x=-1
x=-3

Answer 2

x = - 3, x = - 1

Explanation:

x² + 6x + 3 = 2x ( subtract 2x from both sides )

x² + 4x + 3 = 0 ← in standard form

Consider the factors of the constant term (+ 3) which sum to give the coefficient of the x- term (+ 4)

The factors are + 3 and + 1 , since

3 × 1 = 3 and 3 + 1 = 4 , then

(x + 3)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x + 1 = 0 ⇒ x = - 1