Question

Factorize this does it have Any breaking form??
4a^2+4a-5

Answer 1

• 
  `(2a + 1+√(6))(2a + 1-√(6))`

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Identities we will use:

• 
  `a^2+2ab+b^2=(a+b)^2`
• 
  `a^2-b^2=(a+b)(a-b)`

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Given expression:

• 
  `4a^2+4a-5`

Factorize it by completing the square and setting the difference of squares:

• 
  `4a^2+4a + 1-6=`
• 
  `(2a)^2+2*1*2a + 1^2-6=`
• 
  `(2a+1)^2-6=`
• 
  `(2a + 1+√(6))(2a + 1-√(6))`