Question

Find the slope of the tangent line to k(x)=–2x at x=3.

Answer 1

`-2`

Explanation:

`k(x)=-2x\\k'(x)=-2\\k'(3)=-2`

What I basically did here was take the derivative of the function to find the slope of the function at any given point. Since -2x has a slope of -2, no matter what x is, the slope will always be -2.