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The 6th term of a GP is -2 and its first term is 18 . what is the common ratio

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Solution:

Given conditions:

6th term (T6) = -2

first term (a) = 18

n = 6, r = ?

Formula for finding the nth term of a GP:


tn = a {r}^(n - 1)

Where:

T = the given value for the number of term(s)

n = the given number of term

a = The first term

r = The common ratio

Replacing for the values:


- 2 = 18 {r}^(6 - 1) \\ - 2 = 18 {r}^(5)

Dividing both sides by 18, we have:


{r}^(5) = ( - 2)/(18)

Now, we have to fifth root both sides to find the value of r.


\sqrt[5]{ {r}^(5) } = \sqrt[5]{ ( - 2)/(18) }

Therefore:

Common ratio,
r = -0.0638165752
≈ -0.064 to 3 decimal places.

I hope this helps

User Xudre
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