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How do i solve y=3(0)^3-2(0)^2+13

User Jash Shah
by
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1 Answer

1 vote

Answer:

y = 13

Explanation:

You want to "solve" y=3(0)^3-2(0)^2+13.

Evaluation

An exponent signifies repeated multiplication. That is ...

(0)^3 = 0×0×0

Of course, anything times zero is zero, so the first and second terms are both zero:

3(0)³ -2(0)² = 0 -0 = 0

Adding 0 to 13 does not change its value.

y = 3(0³) -2(0²) +13 = 0 -0 +13

y = 13

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This is one that can be evaluated "by inspection." In general, a polynomial evaluated at x=0 will have the value of the constant term: all of the variable terms become zero.

If that is too much work, you can always enter the expression into your calculator.

User Hader
by
6.7k points