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Let f(x)=−8x+8-6x2 Then the expression hf(x+h)−f(x) can be written in the form Ah+Bx+C, where A, B, and C are constants. (Note: It's possible for one or more of these constants to be 0.) Find the constants.

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Answer:

Hello,

Explanation:


f(x)=-6x^2-8x+8\\\\f(x+h)=-6(x+h)^2-8(x+h)+8-(-6x^2-8x+8)\\=-12xh-6h^2-8h\\=h(-6h-12x-8)\\\\A=-6\\B=-12\\C=-8\\

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