Question

Find two numbers with a sum of 65. Twice the lesser number is 10 more than greater number.

Answer 1

a=25

b=40

Explanation:

We can get two equations from these statements

1.a+b=65

2.a<b

therefore 2a=10+b

and 2a-10=b

substitute into original equation

a+(2a-10)=65

3a=75

a=25

b=65-25

=40