Question

Y=3x + 1 and 5x = y + 3
How to solve this type of simultaneous equation?

Answer 1

(2, 7 )

Explanation:

y = 3x + 1 → (1)

5x = y + 3 → (2)

substitute y = 3x + 1 into (2)

5x = 3x + 1 + 3

5x = 3x + 4 ( subtract 3x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

substitute x = 2 into (1)

y = 3(2) + 1 = 6 + 1 = 7

solution is (2, 7 )