Answer:
Area triangle MNO=12.5 square units.
Perimeter of rectangle JLMO = 30 units.
Area of triangle JKL = 6 square units.
Area of rectangle OJLM = 50 square units.
Area of JKLMNO = 68.5 square units
Explanation:
J = (1,6)
O = (-5,-2)
M = (-1, -5)
N = (-8, -6)
d = sqrt [(x-x)^2 + (y-y)^2]
OM = sqrt[(-1 - 5)^2 + (-5 - - 2)^2
OM = sqrt [(4)^2 + (-3)^2]
OM = sqrt 25 = 5 units
ON = sqrt [(-8 - - 5)^2 + (-6 - - 2)^2]
ON = sqrt 3^2 + -4^2
ON = sqrt 25 = 5 units
OJ = sqrt[(1 - - 5)^2 + (6 - - 2)^2
= sqrt (36 + 64) = sqrt 100 = 10 units
Area of triangle MNO = (5*5)/2 = 12.5 square units
Perimeter of rectangle JLMO = 2(10)+2(5)=30 units
Area of triangle JKL = (4*3)/2 = 6 square units
Area of rectangle OJLM =
(10)*(5)=50 square units
Area of JKLMNO = 6 + 12.5 + 50 = 68.5 square units