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Find the equation of a line parallel to y=−4x+3 that contains the point (3,−3).

HELPPP

User Partoa
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1 Answer

4 votes
Use point slope form and the same slope that’s in the given slope intercept form.
Because the slope is parallel, it’ll just be -4.
The point slope form is
y-y1=m(x-x1)
Substitute the variables for numbers where 3 is x1 and -3 is y1.

y-(-3)=-4(x-3)
Simplify.
y+3=-4x+12
Solve.
Subtract 3 on both sides.
y+3=-4x+12
-3 -3
y=-4x+9
Thus, y=-4x+9 is the solution.

Hope this helps.
User Shafreeck Sea
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