878 views
3 votes
if 3.99 x 10 ^ 13 was written in standard notation how many zeros does it contain before the decimal point

User WCByrne
by
7.3k points

1 Answer

4 votes

Answer:

11 zeros

Explanation:

10^13 = 100 000 000 000 000

Round the two first numbers(which makes 11 zeros left), then lastly the zeros

User Nmadhok
by
7.2k points